The NaOH trap weighed 34.085 g. The P2O5 trap weighed 40.826. The Cathecol reagent bottle weighed 05.160g.
Now, after I got the weight of the Cathecol (05.160g) I had to drag it to the chamber and release it, so all 05.160 was released into the chamber, heat it, and after about a minute, it stopped.
When that finished, I had to take the NaOH trap & weigh that, and the mass of it is 46.460 g.
Then, I had to take the P2O5 trap and weigh that, and the mass of it was 40.826 g.
Next, there is an unknown regeant bottle, and I had to disperse 5g from that and weigh the 5g, and that was 05.101 g. After that, I had to take that and load it into the combustion chamber, heat it and after a minute or so, it stopped.
After that completed, I had to take the NaOH trap and weigh it, and it was 58.472 g.
Then, I had to take the P2O5 trap and weigh it, and the mass of it was 44.104 g
Next, repeat the calculations for the unknown sample above. From the change in the P2O5 and NaOH trap masses, determine the masses of H2O and CO2 produced. Please make sure to use the change in mass of each trap just before, and just after the unknown sample is combusted. Note- do not use the intial masses of the two traps at the start. All of those numbers are included above.
3a – Mass of H20 – ? g
Mass of CO2 – ? g
3b – Convert the above masses into the number of moles of H2O and CO2 produced from the unknown sample.
Moles of H2O – ? moles
Moles of CO2 – ? moles
3c – From the number of moles of H2O and CO2 produced, determine the number of moles of H atoms and C atoms in the sample.
Moles of H atoms – ? moles
Moles of C atoms – ? moles
3d – From the above and the atomic masses of the elements, determine the masses of H and C in the sample.
Mass of H atoms – ? g
Mass of C atoms – ? g
Question 2 –
The mass of O in the unknown sample can obtained by the difference of the sample mass and the total of calculated masses of H and C. Calculate the mass and number of moles of O atoms in the catechol sample.
Mass of O – ? g
Moles of O – ? moles
Question 3 – Determine the simpliest whole number mole ratio of C, H and O in the catechol, and enter this empirical formula for catechol below using just 5 characters (example is C2H30). Do NOT enter subscripts
Type answer as CxHyOz – ?
Hint – The correct empirical formula will use small numbers such as 1, 2, 3, 4