The total energy of the system is 3. Find the amplitude of the motion.

A .255 kg mass is attached to a spring and executes simple harmonic motion with a period of .56 s. The total energy of the system is 3.6 J. Find the amplitude of the motion. Answer in units of mConstant force of the spring is 32.101392 N/m. I figured that out.

Total energy of of any particle executing S.H.M is=E= m ² a² Or, a² = 2E/( mOr, a = ( ²) ) according to the question total energy=3.6 Jtime period of spring = T = 56s = = M= 255 kg So,a= (…

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